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Let’s check out your problem:
What is the sum of the numerical coefficients (including the constant term) of the expanded form of the expression below?
(
t
−
2
)
6
(t-2)^6
(
t
−
2
)
6
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Math Problems
Calculus
Find limits involving absolute value functions
Full solution
Q.
What is the sum of the numerical coefficients (including the constant term) of the expanded form of the expression below?
(
t
−
2
)
6
(t-2)^6
(
t
−
2
)
6
Apply Binomial Theorem:
Use the Binomial Theorem to expand
(
t
−
2
)
6
(t-2)^6
(
t
−
2
)
6
. The Binomial Theorem states that
(
a
−
b
)
n
=
∑
k
=
0
n
(
n
k
)
⋅
a
(
n
−
k
)
⋅
(
−
b
)
k
(a-b)^n = \sum_{k=0}^{n} \binom{n}{k} \cdot a^{(n-k)} \cdot (-b)^k
(
a
−
b
)
n
=
∑
k
=
0
n
(
k
n
)
⋅
a
(
n
−
k
)
⋅
(
−
b
)
k
.
Calculate Coefficients:
Calculate the coefficients for each term in the expansion.
\newline
The coefficients will be determined by
(
(
6
k
)
)
(6 \choose k)
(
k
)
(
6
)
for
k
=
0
k=0
k
=
0
to
6
6
6
.
List Coefficients:
List out the coefficients.
\newline
(
(
6
0
)
=
1
)
(6 \choose 0) = 1
(
0
)
=
1
(
6
)
,
(
(
6
1
)
=
6
)
(6 \choose 1) = 6
(
1
)
=
6
(
6
)
,
(
(
6
2
)
=
15
)
(6 \choose 2) = 15
(
2
)
=
15
(
6
)
,
(
(
6
3
)
=
20
)
(6 \choose 3) = 20
(
3
)
=
20
(
6
)
,
(
(
6
4
)
=
15
)
(6 \choose 4) = 15
(
4
)
=
15
(
6
)
,
(
(
6
5
)
=
6
)
(6 \choose 5) = 6
(
5
)
=
6
(
6
)
,
(
(
6
6
)
=
1
)
(6 \choose 6) = 1
(
6
)
=
1
(
6
)
.
Add Coefficients:
Add up the coefficients.
\newline
Sum =
1
+
6
+
15
+
20
+
15
+
6
+
1
1 + 6 + 15 + 20 + 15 + 6 + 1
1
+
6
+
15
+
20
+
15
+
6
+
1
.
Perform Addition:
Perform the addition.
\newline
Sum =
64
64
64
.
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\newline
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