Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the range of this quadratic function?\newliney=x2+4x+4y = x^2 + 4x + 4\newlineChoices:\newline(A)yy2{y | y \geq -2}\newline(B)yy0{y | y \leq 0}\newline(C)yy0{y | y \geq 0}\newline(D)all real numbers

Full solution

Q. What is the range of this quadratic function?\newliney=x2+4x+4y = x^2 + 4x + 4\newlineChoices:\newline(A)yy2{y | y \geq -2}\newline(B)yy0{y | y \leq 0}\newline(C)yy0{y | y \geq 0}\newline(D)all real numbers
  1. Identify Quadratic Function: Identify the quadratic function and its coefficients.\newlineThe given quadratic function is y=x2+4x+4y = x^2 + 4x + 4. Here, the coefficients are a=1a = 1, b=4b = 4, and c=4c = 4.
  2. Find Vertex x-coordinate: Find the x-coordinate of the vertex of the parabola.\newlineThe x-coordinate of the vertex can be found using the formula x=b2ax = -\frac{b}{2a}. Substituting the values of aa and bb, we get:\newlinex=42×1x = -\frac{4}{2 \times 1}\newlinex=42x = -\frac{4}{2}\newlinex=2x = -2
  3. Find Vertex y-coordinate: Find the y-coordinate of the vertex by substituting the x-coordinate into the original equation.\newlineSubstitute x=2x = -2 into y=x2+4x+4y = x^2 + 4x + 4 to find the y-coordinate of the vertex:\newliney=(2)2+4(2)+4y = (-2)^2 + 4(-2) + 4\newliney=48+4y = 4 - 8 + 4\newliney=0y = 0
  4. Determine Parabola Direction: Determine the direction in which the parabola opens.\newlineSince the coefficient a=1a = 1 is positive, the parabola opens upwards.
  5. Find Range: Find the range of the quadratic function.\newlineThe vertex of the parabola is (2,0)(-2, 0), and since the parabola opens upwards, the range of the function is all yy-values greater than or equal to the yy-coordinate of the vertex.\newlineRange: \{yy0y | y \geq 0\}

More problems from Domain and range of quadratic functions: equations