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What is the radius of the circle x2+y2−64=0x^2 + y^2 - 64 = 0?\newlineSimplify any fractions.\newline____\newline

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Find properties of circles from equations in general formright chevron icon

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Q. What is the radius of the circle x2+y2−64=0x^2 + y^2 - 64 = 0?\newlineSimplify any fractions.\newline____\newline
  1. Move Constant to Other Side: x2+y2−64=0x^2 + y^2 - 64 = 0\newlineMove the constant to the other side.\newlineAdd 6464 on both sides.\newlinex2+y2−64+64=0+64x^2 + y^2 - 64 + 64 = 0 + 64\newlinex2+y2=64x^2 + y^2 = 64
  2. Find Value of r2r^2: x2+y2=64x^2 + y^2 = 64\newlineFind the value of r2r^2 compared to (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2.\newlineStandard form of a circle: (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2\newlineComparing the standard form and x2+y2=64x^2 + y^2 = 64, we see that r2=64r^2 = 64.
  3. Solve for rr: Solve for rr.\newlineTake the square root of both sides.\newliner=r2r = \sqrt{r^2}\newliner=64r = \sqrt{64}\newliner=8r = 8

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