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What is the radius of the circle x2+y2−49=0x^2 + y^2 - 49 = 0?\newlineSimplify any fractions.\newline____\newline

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Find properties of circles from equations in general formright chevron icon

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Q. What is the radius of the circle x2+y2−49=0x^2 + y^2 - 49 = 0?\newlineSimplify any fractions.\newline____\newline
  1. Move Constant: Move the constant to the other side to isolate the terms with xx and yy. Add 4949 to both sides of the equation. x2+y2−49+49=0+49x^2 + y^2 - 49 + 49 = 0 + 49 x2+y2=49x^2 + y^2 = 49
  2. Identify Radius Squared: Identify the radius squared r2r^2 from the equation.\newlineThe standard form of a circle is (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2, where rr is the radius.\newlineComparing x2+y2=49x^2 + y^2 = 49 to the standard form, we see that r2=49r^2 = 49.
  3. Calculate Radius: Calculate the radius rr by taking the square root of r2r^2.r=49r = \sqrt{49}r=7r = 7

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