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What is the missing constant term in the perfect square that starts with x^(2)-16 x ? ◻

What is the missing constant term in the perfect square that starts with x2−16x x^{2}-16 x ?\newline□ \square

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Full solution

Q. What is the missing constant term in the perfect square that starts with x2−16x x^{2}-16 x ?\newline□ \square
  1. Calculate b2\frac{b}{2}: To form a perfect square trinomial from x2−16xx^2 - 16x, we need to add (b2)2\left(\frac{b}{2}\right)^2, where bb is the coefficient of xx.
  2. Calculate (b2)2(\frac{b}{2})^2: Here, b=−16b = -16. So, we calculate (−162)2(\frac{-16}{2})^2.
  3. Calculate (−16/2)2(-16/2)^2: (−16/2)2=(−8)2=64(-16/2)^2 = (-8)^2 = 64.
  4. Find missing constant term: Therefore, the missing constant term is 6464.

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