What is the mean absolute deviation of the temperatures?First Day Temperatures\begin{tabular}{|c|c|}\hline Month & Temperature ∘∘ F) \\\hline January & 9 \\\hline February & 15 \\\hline March & 20 \\\hline April & 18 \\\hline May & 19 \\\hline June & 27 \\\hline\end{tabular}
Q. What is the mean absolute deviation of the temperatures?First Day Temperatures\begin{tabular}{|c|c|}\hline Month & Temperature ∘∘ F) \\\hline January & 9 \\\hline February & 15 \\\hline March & 20 \\\hline April & 18 \\\hline May & 19 \\\hline June & 27 \\\hline\end{tabular}
Calculate Mean: Find the mean of the temperatures.(9+15+20+18+19+27)/6=108/6=18Mean temperature: 18
Absolute Deviations: Calculate the absolute deviations from the mean.∣9−18∣=9∣15−18∣=3∣20−18∣=2∣18−18∣=0∣19−18∣=1∣27−18∣=9
Mean of Deviations: Find the mean of these absolute deviations.(9+3+2+0+1+9)/6=24/6=4Mean absolute deviation: 4
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