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What is the discriminant of the quadratic equation
-x^(2)+8x-8=0 ?
32
96

-96

-32

What is the discriminant of the quadratic equation $-x^{2}+8 x-8=0$ ? $\newline$ $32$ $\newline$ $96$ $\newline$ $-96$ $\newline$ $-32$

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Transformations of functions

Full solution

Q. What is the discriminant of the quadratic equation

-x^{2}+8 x-8=0

?

\newline

32

\newline

96

\newline

-96

\newline

-32

Identify Coefficients: The discriminant of a quadratic equation in the form $ax^2 + bx + c = 0$ is given by the formula $D = b^2 - 4ac$ . We need to identify the coefficients $a$ , $b$ , and $c$ from the given equation and then apply the formula.
Given Quadratic Equation: The given quadratic equation is $-x^2 + 8x - 8 = 0$ . Here, the coefficient $a$ is $-1$ (since the term is $-x^2$ ), the coefficient $b$ is $8$ , and the coefficient $c$ is $-8$ .
Calculate Discriminant: Now we will calculate the discriminant using the formula $D = b^2 - 4ac$ . Substituting the values of $a$ , $b$ , and $c$ , we get $D = (8)^2 - 4\cdot(-1)\cdot(-8)$ .
Perform Calculations: Performing the calculations, we have $D = 64 - 4 \times 1 \times 8$ . This simplifies to $D = 64 - 32$ .
Final Result: After simplifying, we find that $D = 32$ . This is the discriminant of the given quadratic equation.

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