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What is the discriminant of the quadratic equation
4x^(2)+4x+9=0 ?
128

-128

-160
160

What is the discriminant of the quadratic equation $4 x^{2}+4 x+9=0$ ? $\newline$ $128$ $\newline$ $-128$ $\newline$ $-160$ $\newline$ $160$

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Reflections of functions

Full solution

Q. What is the discriminant of the quadratic equation

4 x^{2}+4 x+9=0

?

\newline

128

\newline

-128

\newline

-160

\newline

160

Identify coefficients: The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by the formula $D = b^2 - 4ac$ . Let's identify the coefficients $a$ , $b$ , and $c$ from the given equation $4x^2 + 4x + 9 = 0$ .
Calculate coefficients: The coefficient $a$ is the coefficient of $x^2$ , which is $4$ . The coefficient $b$ is the coefficient of $x$ , which is $4$ . The coefficient $c$ is the constant term, which is $9$ .
Substitute values: Now, let's calculate the discriminant using the formula $D = b^2 - 4ac$ . Substituting the values of $a$ , $b$ , and $c$ , we get $D = (4)^2 - 4(4)(9)$ .
Perform calculations: Performing the calculations, we have $D = 16 - 4(4)(9) = 16 - 144$ .
Final result: Continuing with the calculation, we find $D = 16 - 144 = -128$ .

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