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What is the center of the hyperbola x2y24=0x^2 - y^2 - 4 = 0?\newline(_,_)(\_,\_)

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Q. What is the center of the hyperbola x2y24=0x^2 - y^2 - 4 = 0?\newline(_,_)(\_,\_)
  1. Move constant term: x2y24=0x^2 - y^2 - 4 = 0\newlineMove the constant term to the right side of the equation.\newlinex2y2=4x^2 - y^2 = 4
  2. Convert to standard form: x2y2=4x^2 - y^2 = 4\newlineConvert the equation into standard form for a hyperbola.\newlineDivide both sides of the equation by 44.\newline(x2)/4(y2)/4=4/4(x^2)/4 - (y^2)/4 = 4/4\newlinex2/4y2/4=1x^2/4 - y^2/4 = 1
  3. Find center: x24y24=1\frac{x^2}{4} - \frac{y^2}{4} = 1\newlineFind the center of the hyperbola.\newlineThe equation can be written as (x0)2/4(y0)2/4=1\left(x - 0\right)^2/4 - \left(y - 0\right)^2/4 = 1.\newlineHere h=0h = 0, k=0k = 0.\newlineCenter of the hyperbola: (0,0)(0, 0)

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