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What is the center of the hyperbola x2−9y2=36x^2 - 9y^2 = 36?\newline(_,_)(\_,\_)

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Find properties of hyperbolas from equations in general formright chevron icon

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Q. What is the center of the hyperbola x2−9y2=36x^2 - 9y^2 = 36?\newline(_,_)(\_,\_)
  1. Move constant to right: x2−9y2=36x^2 - 9y^2 = 36\newlineMove the constant term to the right side to set the equation up for standard form.\newlinex2−9y2−36+36=36x^2 - 9y^2 - 36 + 36 = 36\newlinex2−9y2=36x^2 - 9y^2 = 36
  2. Convert to standard form: x2−9y2=36x^2 - 9y^2 = 36\newlineConvert the equation into standard form by dividing both sides by 3636.\newlinex236−9y236=3636\frac{x^2}{36} - \frac{9y^2}{36} = \frac{36}{36}\newlinex2/36−y2/4=1x^2/36 - y^2/4 = 1
  3. Find center of hyperbola: x236−y24=1\frac{x^2}{36} - \frac{y^2}{4} = 1\newlineFind the center of the hyperbola.\newlineThe equation can be written as (x−0)2/36−(y−0)2/4=1\left(x - 0\right)^2/36 - \left(y - 0\right)^2/4 = 1.\newlineHere h=0h = 0, k=0k = 0.\newlineCenter of the hyperbola: (0,0)(0, 0)

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