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What is the center of the circle passing through (−2,1)(-2, 1) and tangent to the line 3x−2y−6=03x - 2y - 6 = 0 at the point (4,3)(4, 3)?

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Find properties of circles from equations in general formright chevron icon

Full solution

Q. What is the center of the circle passing through (−2,1)(-2, 1) and tangent to the line 3x−2y−6=03x - 2y - 6 = 0 at the point (4,3)(4, 3)?
  1. Find Circle Equation: Step 11: Find the equation of the circle passing through (−2,1)(-2, 1) and tangent to the line at (4,3)(4, 3).
  2. Calculate Radius: Step 22: Use the point-line distance formula to express the radius.
  3. Correct Mistake: Step 33: Since the calculated radius is 00, which is not possible for a circle that passes through another point, there must be a mistake in the calculation.

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