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What is the center of the circle x2+y2=144x^2 + y^2 = 144??\newlineSimplify any fractions.\newline(__,__)\newline

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Q. What is the center of the circle x2+y2=144x^2 + y^2 = 144??\newlineSimplify any fractions.\newline(__,__)\newline
  1. Equation of a Circle: The equation of a circle in standard form is (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) is the center of the circle and rr is the radius. We need to compare the given equation x2+y2=144x^2 + y^2 = 144 with the standard form to find the values of hh and kk.
  2. Rewriting the Given Equation: The given equation x2+y2=144x^2 + y^2 = 144 can be rewritten as (x−0)2+(y−0)2=144(x - 0)^2 + (y - 0)^2 = 144 to match the standard form. This implies that h=0h = 0 and k=0k = 0, since there are no values being subtracted from xx and yy in the given equation.
  3. Finding the Center of the Circle: Since we have found that h=0h = 0 and k=0k = 0, the center of the circle described by the equation x2+y2=144x^2 + y^2 = 144 is at the point (0,0)(0, 0).

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