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What is (f−g)(x)(f - g)(x)?\newlinef(x)=−4xf(x) = -4x\newlineg(x)=−2x2+2xg(x) = -2x^2 + 2x\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______

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Q. What is (f−g)(x)(f - g)(x)?\newlinef(x)=−4xf(x) = -4x\newlineg(x)=−2x2+2xg(x) = -2x^2 + 2x\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______
  1. Identify formula: Identify the formula for (f−g)(x)(f - g)(x). \newline(f−g)(x)(f - g)(x) is the difference of f(x)f(x) and g(x)g(x). \newline(f−g)(x)=f(x)−g(x)(f - g)(x) = f(x) - g(x)
  2. Substitute f(x)f(x) and g(x)g(x): We have: \newlinef(x)=−4xf(x) = -4x \newlineg(x)=−2x2+2xg(x) = -2x^2 + 2x \newlineSubstitute f(x)f(x) and g(x)g(x) into the formula for (f−g)(x)(f - g)(x). \newline(f−g)(x)=f(x)−g(x)(f - g)(x) = f(x) - g(x) \newline(f−g)(x)=(−4x)−(−2x2+2x)(f - g)(x) = (-4x) - (-2x^2 + 2x)
  3. Simplify expression: Simplify the expression by distributing the negative sign and combining like terms. \newline(f−g)(x)=−4x+2x2−2x(f - g)(x) = -4x + 2x^2 - 2x \newline(f−g)(x)=2x2−4x−2x(f - g)(x) = 2x^2 - 4x - 2x \newline(f−g)(x)=2x2−6x(f - g)(x) = 2x^2 - 6x

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