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(-30 i)+(52-30 i)= Express your answer in the form (a+bi).

(−30i)+(52−30i)= (-30 i)+(52-30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

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Composition of linear functions: find an equationright chevron icon

Full solution

Q. (−30i)+(52−30i)= (-30 i)+(52-30 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Combine complex numbers: To add two complex numbers, we combine the real parts and the imaginary parts separately.\newline(−30i)+(52−30i)=(0+52)+(−30i−30i)(-30i) + (52 - 30i) = (0 + 52) + (-30i - 30i)
  2. Add real parts: Now, we add the real parts: 0+52=520 + 52 = 52.\newlineAnd we add the imaginary parts: −30i−30i=−60i-30i - 30i = -60i.
  3. Add imaginary parts: Combine the real and imaginary parts to express the sum in the form (a+bi)(a + bi).\newlineThe sum is 52−60i52 - 60i.

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