Q. We are given that dxdy=x2−2y.Fasind an expression for dx2d2y in terms of x and y.dx2d2y=
Given Derivative Equation: We are given the first derivative of y with respect to x as dxdy=x2−2y. To find the second derivative dx2d2y, we need to differentiate dxdy with respect to x.
Apply Chain Rule: Differentiate dxdy with respect to x using the chain rule for the term −2y, since y is a function of x. This means we need to multiply the derivative of −2y with respect to y, which is −2, by the derivative of y with respect to x, which is dxdy.
Calculate Second Derivative: The derivative of x2 with respect to x is 2x. The derivative of −2y with respect to y is −2, and we multiply this by (dy)/(dx) to apply the chain rule. So, the second derivative (d2y)/(dx2) is 2x−2(dy)/(dx).
Substitute and Simplify: Substitute the expression for dxdy from the given equation into the expression for dx2d2y. This gives us dx2d2y=2x−2(x2−2y).
Final Second Derivative Expression: Simplify the expression for (d2y)/(dx2) by distributing the −2 and combining like terms. This gives us (d2y)/(dx2)=2x−2x2+4y.
Final Second Derivative Expression: Simplify the expression for (d2y)/(dx2) by distributing the −2 and combining like terms. This gives us (d2y)/(dx2)=2x−2x2+4y.The final expression for the second derivative of y with respect to x in terms of x and y is (d2y)/(dx2)=−2x2+2x+4y.
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