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Uche pumps gasoline at a rate of 18 Lmin\frac{18\,\text{L}}{\text{min}}. What is Uche's pumping rate in mLs\frac{\text{mL}}{\text{s}} ?

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Full solution

Q. Uche pumps gasoline at a rate of 18 Lmin\frac{18\,\text{L}}{\text{min}}. What is Uche's pumping rate in mLs\frac{\text{mL}}{\text{s}} ?
  1. Convert Units: Convert Uche's pumping rate from liters per minute to milliliters per second. We know that 11 liter is equal to 10001000 milliliters, and there are 6060 seconds in a minute.
  2. Convert Liters to Milliliters: First, convert the rate from liters to milliliters by multiplying by 10001000.18(L/min)×1000(mL/L)=18000(mL/min)18(\text{L/min}) \times 1000(\text{mL/L}) = 18000(\text{mL/min})
  3. Convert Minutes to Seconds: Next, convert the rate from minutes to seconds by dividing by 6060, since there are 6060 seconds in a minute.\newline18000(mL/min)60(s/min)=300(mL/s)\frac{18000(\text{mL/min})}{60(\text{s/min})} = 300(\text{mL/s})
  4. Final Pumping Rate: Uche's pumping rate is therefore 300300 milliliters per second.

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