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There are two spinners containing only white and orange slices.
Spinner A has 4 white slices and 1 orange slice.
All the slices are the same size.
Spinner B has 12 white slices and 4 orange slices.
All the slices are the same size.
Each spinner is spun.
List these events from least likely to most likely.
Event 1: Spinner B lands on a white slice.
Event 2: Spinner A lands on a white slice.
Event 3: Spinner B lands on a white or orange slice.
Event 4: Spinner
A lands on an orange slice.

Least likely

longrightarrow
Most likely

Event 4
Event 4
Event 2
Event 3

There are two spinners containing only white and orange slices. $\newline$ Spinner A has $4$ white slices and $1$ orange slice. $\newline$ All the slices are the same size. $\newline$ Spinner B has $12$ white slices and $4$ orange slices. $\newline$ All the slices are the same size. $\newline$ Each spinner is spun. $\newline$ List these events from least likely to most likely. $\newline$ Event $1$ : Spinner B lands on a white slice. $\newline$ Event $2$ : Spinner A lands on a white slice. $\newline$ Event $3$ : Spinner B lands on a white or orange slice. $\newline$ Event $4$ : Spinner $\mathrm{A}$ lands on an orange slice. $\newline$ \begin{tabular}{|c|c|c|c|} $\newline$ \hline Least likely & & $\longrightarrow$ & Most likely \\ $\newline$ \hline Event $4$ & Event $4$ & Event $2$ & Event $3$ \\ $\newline$ \hline $\newline$ \end{tabular}

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Full solution

Q. There are two spinners containing only white and orange slices.

\newline

Spinner A has

4

white slices and

1

orange slice.

\newline

All the slices are the same size.

\newline

Spinner B has

12

white slices and

4

orange slices.

\newline

All the slices are the same size.

\newline

Each spinner is spun.

\newline

List these events from least likely to most likely.

\newline

Event

1

: Spinner B lands on a white slice.

\newline

Event

2

: Spinner A lands on a white slice.

\newline

Event

3

: Spinner B lands on a white or orange slice.

\newline

Event

4

: Spinner

\mathrm{A}

lands on an orange slice.

\newline

\begin{tabular}{|c|c|c|c|}

\newline

\hline Least likely & &

\longrightarrow

& Most likely \\

\newline

\hline Event

4

& Event

4

& Event

2

& Event

3

\newline

\hline

\newline

\end{tabular}

Calculate Probability Event $1$ : Calculate the probability of Event $1$ : Spinner B lands on a white slice. $\newline$ Probability(Event $1$ ) = $\frac{\text{Number of white slices on Spinner B}}{\text{Total number of slices on Spinner B}}$ $\newline$ Probability(Event $1$ ) = $\frac{12}{12 + 4}$ $\newline$ Probability(Event $1$ ) = $\frac{12}{16}$ $\newline$ Probability(Event $1$ ) = $\frac{3}{4}$
Calculate Probability Event $2$ : Calculate the probability of Event $2$ : Spinner A lands on a white slice. $\newline$ Probability(Event $2$ ) = Number of white slices on Spinner A / Total number of slices on Spinner A $\newline$ Probability(Event $2$ ) = $\frac{4}{4 + 1}$ $\newline$ Probability(Event $2$ ) = $\frac{4}{5}$
Calculate Probability Event $3$ : Calculate the probability of Event $3$ : Spinner B lands on a white or orange slice. $\newline$ Since there are only white and orange slices, the probability is $100\%$ . $\newline$ $\text{Probability(Event 3)} = \frac{\text{Total number of slices on Spinner B}}{\text{Total number of slices on Spinner B}}$ $\newline$ $\text{Probability(Event 3)} = \frac{(12 + 4)}{(12 + 4)}$ $\newline$ $\text{Probability(Event 3)} = \frac{16}{16}$ $\newline$ $\text{Probability(Event 3)} = 1$
Calculate Probability Event $4$ : Calculate the probability of Event $4$ : Spinner A lands on an orange slice. $\newline$ Probability(Event $4$ ) = $\frac{\text{Number of orange slices on Spinner A}}{\text{Total number of slices on Spinner A}}$ $\newline$ Probability(Event $4$ ) = $\frac{1}{4 + 1}$ $\newline$ Probability(Event $4$ ) = $\frac{1}{5}$
List Events by Likelihood: List the events from least likely to most likely. $\newline$ Comparing the probabilities: $\newline$ Probability(Event $4$ ) = $\frac{1}{5}$ $\newline$ Probability(Event $2$ ) = $\frac{4}{5}$ $\newline$ Probability(Event $1$ ) = $\frac{3}{4}$ $\newline$ Probability(Event $3$ ) = $1$ $\newline$ Least likely is Event $4$ , then Event $1$ , followed by Event $2$ , and most likely is Event $3$ .