$19$ ) The value of $y$ varies directly with $x$ . When $y=25, x=3 / 4$ . What is the value of $y$ when $x$ is $4$ . $875$ ? $\newline$ $81$ . $25$ $\newline$ $121$ . $875$ $\newline$ iv $\newline$ $103$ . $125$ $\newline$ $162$ . $5$

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Grade 6

Multiply two decimals: where does the decimal point go?

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19

) The value of

y

varies directly with

x

. When

y=25, x=3 / 4

. What is the value of

y

when

x

4

875

\newline

81

25

\newline

121

875

\newline

\newline

103

125

\newline

162

5

Find Constant of Variation: First, we need to find the constant of variation $k$ , since $y$ varies directly with $x$ , we can say $y = kx$ . So let's plug in the values we know, which are $y=25$ and $x=\frac{3}{4}$ .
Calculate Constant k: Now, calculate the constant k by dividing y by x. So, $k = \frac{25}{\frac{3}{4}}$ .
Determine $y$ for $x=4.875$ : After doing the division, we get $k = \frac{25}{(3/4)} = 25 \times (4/3) = \frac{100}{3}$ .
Determine $y$ for $x=4.875$ : After doing the division, we get $k = \frac{25}{(3/4)} = 25 \times (4/3) = \frac{100}{3}$ .Now we have the constant of variation $k$ , we can find $y$ for any $x$ using the formula $y = kx$ . We need to find $y$ when $x$ is $4.875$ , so plug these values into the equation.
Determine $y$ for $x=4.875$ : After doing the division, we get $k = \frac{25}{(3/4)} = 25 \times (4/3) = \frac{100}{3}$ .Now we have the constant of variation $k$ , we can find $y$ for any $x$ using the formula $y = kx$ . We need to find $y$ when $x$ is $4.875$ , so plug these values into the equation.So, $x=4.875$ $0$ . Let's do the multiplication to find $y$ .
Determine $y$ for $x=4.875$ : After doing the division, we get $k = \frac{25}{(3/4)} = 25 \times (4/3) = \frac{100}{3}$ .Now we have the constant of variation $k$ , we can find $y$ for any $x$ using the formula $y = kx$ . We need to find $y$ when $x$ is $4.875$ , so plug these values into the equation.So, $x=4.875$ $0$ . Let's do the multiplication to find $y$ .Multiplying these together, $x=4.875$ $2$ .