Q. 3. The temperature was 4∘F at 10:00 PM. It dropped an average of 3∘ each hour for the next 6 hours. What was the temperature at 4:00 AM?
Initial Temperature: Initial temperature at 10:00 PM: 4°FTemperature drop per hour: 3°FTotal hours of temperature drop: 6 hoursCalculate total temperature drop: 3°F/hour×6 hours
Total Temperature Drop: Total temperature drop: 3∘F/hour×6hours=18∘FSubtract total drop from initial temperature: 4∘F−18∘F
Final Temperature: Final temperature at 4:00 AM: 4°F−18°F=−14°F
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