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Ella deposited 
$2500 into a savings account.
The relationship between the time, 
t, in years, since the account was first opened, and Ella's account balance, 
B(t), in dollars, is modeled by the following function.

B(t)=2500*e^(0.025 t)
What will the balance of Ella's savings account be after 4 years? Round your answer, if necessary, to the nearest hundredth.

$

Ella deposited $2500 \$ 2500 into a savings account.\newlineThe relationship between the time, t t , in years, since the account was first opened, and Ella's account balance, B(t) B(t) , in dollars, is modeled by the following function.\newlineB(t)=2500e0.025t B(t)=2500 \cdot e^{0.025 t} \newlineWhat will the balance of Ella's savings account be after 44 years? Round your answer, if necessary, to the nearest hundredth.\newline$ \$

Full solution

Q. Ella deposited $2500 \$ 2500 into a savings account.\newlineThe relationship between the time, t t , in years, since the account was first opened, and Ella's account balance, B(t) B(t) , in dollars, is modeled by the following function.\newlineB(t)=2500e0.025t B(t)=2500 \cdot e^{0.025 t} \newlineWhat will the balance of Ella's savings account be after 44 years? Round your answer, if necessary, to the nearest hundredth.\newline$ \$
  1. Identify Given Information: Identify the given information and the formula to use.\newlineWe are given the initial deposit amount (2500),theannualinterestrateintheformofanexponentialgrowthrate(2500), the annual interest rate in the form of an exponential growth rate (00.025025),andthetimeperiod(), and the time period (44years).Wewillusetheexponentialgrowthformula years). We will use the exponential growth formula B(t) = 25002500 \cdot e^{00.025025 \cdot t}tocalculatethebalanceafter to calculate the balance after 44$ years.
  2. Substitute Values into Formula: Substitute the given values into the formula.\(\newline\)We need to substitute \(t = 4\) into the formula to find \(B(4)\), which represents the balance after \(4\) years.\(\newline\)\(B(4) = 2500 \times e^{(0.025 \times 4)}\)
  3. Calculate Exponent Part: Calculate the exponent part of the formula.\(\newline\)\(0.025 \times 4 = 0.1\)\(\newline\)Now we have \(B(4) = 2500 \times e^{0.1}\)
  4. Calculate Value of \(e^{0.1}\): Calculate the value of \(e^{0.1}\). Using a calculator, we find that \(e^{0.1} \approx 1.105170918\)
  5. Multiply Initial Amount: Multiply the initial amount by the calculated exponential factor to find the balance.\(\newline\)\(B(4) = 2500 \times 1.105170918\)\(\newline\)\(B(4) \approx 2762.927295\)
  6. Round to Nearest Hundredth: Round the result to the nearest hundredth as instructed.\(\newline\)B(\(4\)) \(\approx\) \(\$2762.93\)

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