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The sum of two numbers is 2727 and product is 182182. The numbers are:\newline1010 and 1515\newline1818 and 1414\newline1212 and 1515\newline1111 and 2424

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Q. The sum of two numbers is 2727 and product is 182182. The numbers are:\newline1010 and 1515\newline1818 and 1414\newline1212 and 1515\newline1111 and 2424
  1. Denote numbers xx and yy: Let's denote the two numbers as xx and yy. According to the problem, we have two equations:\newline11) x+y=27x + y = 27 (Sum of the two numbers)\newline22) xy=182xy = 182 (Product of the two numbers)\newlineWe need to find the values of xx and yy that satisfy both equations.
  2. Express yy in terms of xx: We can express yy in terms of xx using the first equation: y=27xy = 27 - x.
  3. Substitute yy into second equation: Now we substitute y=27xy = 27 - x into the second equation to find xx:x(27x)=182x(27 - x) = 182Expanding this, we get:27xx2=18227x - x^2 = 182
  4. Rearrange to form quadratic equation: Rearrange the equation to form a quadratic equation:\newlinex227x+182=0x^2 - 27x + 182 = 0
  5. Factor quadratic equation: We can factor this quadratic equation to find the values of xx:(x14)(x13)=0(x - 14)(x - 13) = 0
  6. Find possible values for x: Setting each factor equal to zero gives us the possible values for x:\newlinex14=0x - 14 = 0 or x13=0x - 13 = 0\newlineSo, x=14x = 14 or x=13x = 13
  7. Calculate corresponding values for y: If x=14x = 14, then y=27x=2714=13y = 27 - x = 27 - 14 = 13. If x=13x = 13, then y=27x=2713=14y = 27 - x = 27 - 13 = 14.
  8. Check product for both pairs: We check the product for both pairs to ensure there's no math error:\newlineFor x=14x = 14 and y=13y = 13: 14×13=18214 \times 13 = 182\newlineFor x=13x = 13 and y=14y = 14: 13×14=18213 \times 14 = 182\newlineBoth pairs give the correct product, so there is no math error.

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