Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Write the sentence as an equation. $\newline$ $172$ is equal to the quotient of $x$ and $4$ $\newline$ Type a slash ( $/$ ) if you want to use a division sign. $\newline$ _____

View step-by-step help

View step-by-step help

Solve equations using cube roots

Full solution

Q. Write the sentence as an equation.

\newline

172

is equal to the quotient of

x

and

4

\newline

Type a slash (

/

) if you want to use a division sign.

\newline

_____

Write Equation: $172$ equals the quotient of $x$ and $4$ . So, the equation is $172 = \frac{x}{4}$ .
Solve for x: To check if the equation is correct, solve for $x$ . Multiply both sides by $4$ to isolate $x$ . $4 \times 172 = x$ .
Calculate $x$ : Calculate the product of $4$ and $172$ . $4 \times 172 = 688$ .So, $x = 688$ .

More problems from Solve equations using cube roots

Question

\sqrt{49}

?

\newline

Posted 1 month ago

Question

Complete the following statement. Use the integers that are closest to the number in the middle.

\newline

<

\sqrt{40}

<

Posted 1 month ago

Question

-\sqrt{64}

\newline

Posted 2 months ago

Question

\sqrt[3]{27}

Posted 1 month ago

Question

Which two integers is

-\sqrt{48}

\newline

\newline

[A]-6 \text{ and } -5

\newline

[B]5 \text{ and } 6

\newline

[C]-7 \text{ and } -6

\newline

[D]6 \text{ and } 7

Posted 6 days ago

Question

What is the cube root of

-64

\newline

Posted 2 months ago

Question

Which two integers is

\sqrt[3]{22}

\newline

\newline

[1 \text{ and } 2]

\newline

[15 \text{ and } 16]

\newline

[16 \text{ and } 17]

\newline

[2 \text{ and } 3]

Posted 2 months ago

Question

\newline

(\sqrt{25})^2 = \_\_\_\_\_

Posted 1 month ago

Question

Look at this equation:

\newline

c^3 = 27

\newline

\newline

c

, the cube root of

27

\newline

c =

\newline

Posted 2 months ago

Question

-1

1

1

}{x}\sqrt{\frac{

1

1

-x}}\ln{\left(\frac{

2

2

2

1

2

2

-2

1

Posted 10 hours ago