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The radius of the base of a cone is decreasing at a rate of $2$ centimeters per minute.$\newline$The height of the cone is fixed at $9$ centimeters.$\newline$At a certain instant, the radius is $13$ centimeters.$\newline$What is the rate of change of the volume of the cone at that instant (in cubic centimeters per minute)?$\newline$Choose $1$ answer:$\newline$(A) $-156 \pi$$\newline$(B) $-78 \pi$$\newline$(C) $-507 \pi$$\newline$(D) $-12 \pi$$\newline$The volume of a cone with radius $r$ and height $h$ is $\pi r^{2} \frac{h}{3}$.