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v=sqrt((3RT)/(M))
The root-mean-square speed is the measure of the speed of particles in a gas. Root-mean-square speed, 
v, can be calculated using the equation shown, where 
M is the molar mass of a gas, 
R is the molar gas constant, and 
T is the temperature. Which of the following equations correctly expresses the molar mass of a gas in terms of root-mean-square speed, temperature, and the molar gas constant?
Choose 1 answer:
(A) 
M=((3RT)/(v))^(2)
(B) 
M=(3RT)/((v)^(2))
(C) 
M=((v)^(2))/(3RT)
(D) 
M=(sqrt(3RT))/(v)

v=3RTM v=\sqrt{\frac{3 R T}{M}} \newlineThe root-mean-square speed is the measure of the speed of particles in a gas. Root-mean-square speed, v v , can be calculated using the equation shown, where M M is the molar mass of a gas, R R is the molar gas constant, and T T is the temperature. Which of the following equations correctly expresses the molar mass of a gas in terms of root-mean-square speed, temperature, and the molar gas constant?\newlineChoose 11 answer:\newline(A) M=(3RTv)2 M=\left(\frac{3 R T}{v}\right)^{2} \newline(B) M=3RT(v)2 M=\frac{3 R T}{(v)^{2}} \newline(C) M=(v)23RT M=\frac{(v)^{2}}{3 R T} \newline(D) M=3RTv M=\frac{\sqrt{3 R T}}{v}

Full solution

Q. v=3RTM v=\sqrt{\frac{3 R T}{M}} \newlineThe root-mean-square speed is the measure of the speed of particles in a gas. Root-mean-square speed, v v , can be calculated using the equation shown, where M M is the molar mass of a gas, R R is the molar gas constant, and T T is the temperature. Which of the following equations correctly expresses the molar mass of a gas in terms of root-mean-square speed, temperature, and the molar gas constant?\newlineChoose 11 answer:\newline(A) M=(3RTv)2 M=\left(\frac{3 R T}{v}\right)^{2} \newline(B) M=3RT(v)2 M=\frac{3 R T}{(v)^{2}} \newline(C) M=(v)23RT M=\frac{(v)^{2}}{3 R T} \newline(D) M=3RTv M=\frac{\sqrt{3 R T}}{v}
  1. Square Both Sides: We start with the given equation for root-mean-square speed: v=(3RTM)v = \sqrt{(\frac{3RT}{M})}. To solve for MM, we need to square both sides of the equation to get rid of the square root. v2=3RTMv^2 = \frac{3RT}{M}
  2. Multiply by M: Next, we multiply both sides by M to get M on one side of the equation by itself.\newlineMv2=3RTM \cdot v^2 = 3RT
  3. Divide by v2v^2: Now, we divide both sides by v2v^2 to isolate MM.\newlineM=3RTv2M = \frac{3RT}{v^2}

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