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The points (−9,a)(-9,a) and (−7,−10)(-7,-10) fall on a line with a slope of −7-7. What is the value of aa?\newlinea = ____

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Q. The points (−9,a)(-9,a) and (−7,−10)(-7,-10) fall on a line with a slope of −7-7. What is the value of aa?\newlinea = ____
  1. Identify Points and Slope: Identify the given points and the slope.\newlinePoints: (−9,a)(-9, a) and (−7,−10)(-7, -10)\newlineSlope: −7-7\newlineWe will use the slope formula to find the value of aa.\newlineSlope = (y2−y1)/(x2−x1)(y_2 - y_1)/(x_2 - x_1)\newline−7=(−10−a)/(−7−(−9))-7 = (-10 - a) / (-7 - (-9))
  2. Simplify Denominator: Simplify the denominator of the slope equation.\newline−7=−10−a−7+9-7 = \frac{-10 - a}{-7 + 9}\newline−7=−10−a2-7 = \frac{-10 - a}{2}
  3. Multiply by 22: Multiply both sides of the equation by 22 to isolate the term with aa.−7×2=−10−a2×2-7 \times 2 = \frac{-10 - a}{2} \times 2−14=−10−a-14 = -10 - a
  4. Add 1010: Add 1010 to both sides of the equation to solve for aa. \newline−14+10=−10−a+10-14 + 10 = -10 - a + 10\newline−4=−a-4 = -a
  5. Multiply by −1-1: Multiply both sides by −1-1 to find the value of aa.−1×−4=−1×−a-1 \times -4 = -1 \times -a4=a4 = a

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