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The points (−8,z)(-8,z) and (−9,−2)(-9,-2) fall on a line with a slope of 1010. What is the value of zz?\newlinez=___z = \_\_\_

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Q. The points (−8,z)(-8,z) and (−9,−2)(-9,-2) fall on a line with a slope of 1010. What is the value of zz?\newlinez=___z = \_\_\_
  1. Set up slope equation: Points: (−8,z)(-8, z) and (−9,−2)(-9, -2)\newlineSlope: 1010\newlineUse the slope formula to set up the equation.\newlineSlope = y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}\newline10=z−(−2)−8−(−9)10 = \frac{z - (-2)}{-8 - (-9)}
  2. Simplify equation: Simplify the right side of the equation. 10=z+2110 = \frac{z + 2}{1}
  3. Isolate z+2z + 2: Multiply both sides by 11 to isolate z+2z + 2.\newline10×1=(z+2)×110 \times 1 = (z + 2) \times 1\newline10=z+210 = z + 2
  4. Solve for z: Solve for z.\newline10=z+210 = z + 2\newline10−2=z+2−210 - 2 = z + 2 - 2\newline8=z8 = z

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