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The points (8,f)(8,f) and (10,8)(10,8) fall on a line with a slope of 44. What is the value of ff?\newlinef=___f = \_\_\_

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Full solution

Q. The points (8,f)(8,f) and (10,8)(10,8) fall on a line with a slope of 44. What is the value of ff?\newlinef=___f = \_\_\_
  1. Calculate Slope: Points: (8,f)(8, f) and (10,8)(10, 8); Slope: 44\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline4=8−f10−84 = \frac{8 - f}{10 - 8}
  2. Simplify Denominator: Simplify the denominator: 4=8−f24 = \frac{8 - f}{2}
  3. Isolate Term with f: Multiply both sides by 22 to isolate the term with ff:4×2=8−f2×24 \times 2 = \frac{8 - f}{2} \times 28=8−f8 = 8 - f

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