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The points (−8,−2)(-8,-2) and (−7,h)(-7,h) fall on a line with a slope of −6-6. What is the value of hh?\newlineh=___h = \_\_\_

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Q. The points (−8,−2)(-8,-2) and (−7,h)(-7,h) fall on a line with a slope of −6-6. What is the value of hh?\newlineh=___h = \_\_\_
  1. Identify Given Points and Slope: Step 11: Identify the given points and slope.\newlinePoints: (−8,−2)(-8, -2) and (−7,h)(-7, h)\newlineSlope: −6-6\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−6=h−(−2)−7−(−8)-6 = \frac{h - (-2)}{-7 - (-8)}
  2. Simplify the Equation: Step 22: Simplify the equation.\newline−6=(h+2)(−7+8)-6 = \frac{(h + 2)}{(-7 + 8)}\newline−6=(h+2)−1-6 = \frac{(h + 2)}{-1}
  3. Solve for h: Step 33: Solve for h.\newlineMultiply both sides by −1-1 to isolate h+2h + 2.\newline−6×−1=(h+2)×−1-6 \times -1 = (h + 2) \times -1\newline6=−h−26 = -h - 2
  4. Isolate hh: Step 44: Isolate hh.6+2=−h6 + 2 = -h8=−h8 = -hh=−8h = -8

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