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The points (8,10)(-8,-10) and (9,n)(-9,n) fall on a line with a slope of 9-9. What is the value of nn?\newlinen=___n = \_\_\_

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Q. The points (8,10)(-8,-10) and (9,n)(-9,n) fall on a line with a slope of 9-9. What is the value of nn?\newlinen=___n = \_\_\_
  1. Calculate Slope: Points: (8,10)(-8, -10) and (9,n)(-9, n)\newlineSlope: 9-9\newlineUse the slope formula to relate the points and the slope.\newlineSlope = y2y1x2x1\frac{y_2 - y_1}{x_2 - x_1}\newline9=n(10)9(8)-9 = \frac{n - (-10)}{-9 - (-8)}
  2. Simplify Equation: 9=n(10)9(8)-9 = \frac{n - (-10)}{-9 - (-8)}\newlineSimplify the right side of the equation.\newline9=n+109+8-9 = \frac{n + 10}{-9 + 8}\newline9=n+101-9 = \frac{n + 10}{-1}
  3. Isolate nn: 9=n+101-9 = \frac{n + 10}{-1}\newlineMultiply both sides by 1-1 to isolate n+10n + 10.\newline9×1=n+101×1-9 \times -1 = \frac{n + 10}{-1} \times -1\newline9=n+109 = n + 10
  4. Solve for nn: 9=n+109 = n + 10 Solve for nn by subtracting 1010 from both sides. 910=n+10109 - 10 = n + 10 - 10 1=n-1 = n

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