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The points (−7,t)(-7,t) and (−6,2)(-6,2) fall on a line with a slope of 1010. What is the value of tt?\newlinet=___t = \_\_\_

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Full solution

Q. The points (−7,t)(-7,t) and (−6,2)(-6,2) fall on a line with a slope of 1010. What is the value of tt?\newlinet=___t = \_\_\_
  1. Calculate slope formula: Calculate the slope using the formula for slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2): y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}. Here, x1=−7x_1 = -7, y1=ty_1 = t, x2=−6x_2 = -6, y2=2y_2 = 2.
  2. Set equal and solve: Set the calculated slope equal to the given slope of the line, which is 1010, and solve for tt.

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