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The points 
(-6,r) and 
(10,-2) lie on a line with slope 
-(3)/(4). Find the missing coordinate 
r.

r=

The points (6,r) (-6, r) and (10,2) (10,-2) lie on a line with slope 34 -\frac{3}{4} . Find the missing coordinate r r .\newliner= r=

Full solution

Q. The points (6,r) (-6, r) and (10,2) (10,-2) lie on a line with slope 34 -\frac{3}{4} . Find the missing coordinate r r .\newliner= r=
  1. Identify Points and Slope: Identify the given points and the slope of the line.\newlinePoints: (6,r)(-6, r) and (10,2)(10, -2)\newlineSlope: (34)-\left(\frac{3}{4}\right)\newlineUse the slope formula to set up the equation.\newlineSlope =y2y1x2x1= \frac{y_2 - y_1}{x_2 - x_1}\newline(34)=2r10(6)-\left(\frac{3}{4}\right) = \frac{-2 - r}{10 - (-6)}
  2. Set Up Equation: Simplify the right side of the equation.\newline34=2r10+6-\frac{3}{4} = \frac{-2 - r}{10 + 6}\newline34=2r16-\frac{3}{4} = \frac{-2 - r}{16}
  3. Simplify Equation: Cross-multiply to solve for rr.34×16=2r-\frac{3}{4} \times 16 = -2 - r3×4=2r-3 \times 4 = -2 - r12=2r-12 = -2 - r
  4. Cross-Multiply to Solve: Solve for rr.
    12=2r-12 = -2 - r
    12+2=2r+2-12 + 2 = -2 - r + 2
    10=r-10 = -r
    r=10r = 10

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