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The points (−6,f)(-6,f) and (−7,−9)(-7,-9) fall on a line with a slope of 1010. What is the value of ff?\newlinef=___f = \_\_\_

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Q. The points (−6,f)(-6,f) and (−7,−9)(-7,-9) fall on a line with a slope of 1010. What is the value of ff?\newlinef=___f = \_\_\_
  1. Identify Given Points and Slope: Identify the given points and slope.\newlinePoints: (−6,f)(-6, f) and (−7,−9)(-7, -9); Slope =10= 10.\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}.\newline10=f−(−9)−6−(−7)10 = \frac{f - (-9)}{-6 - (-7)}.
  2. Use Slope Formula: Simplify the equation.\newline10=f+9−6+710 = \frac{f + 9}{-6 + 7}.\newline10=f+9−110 = \frac{f + 9}{-1}.
  3. Simplify the Equation: Solve for ff.\newlineMultiply both sides by −1-1 to isolate f+9f + 9.\newline10×−1=(f+9)×−110 \times -1 = (f + 9) \times -1.\newline−10=−f−9-10 = -f - 9.
  4. Solve for ff: Isolate ff.-10 + 9 = -f - 9 + 9\.-1 = -f\.f = 1\.

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