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The points (5,7)(-5,7) and (6,g)(-6,g) fall on a line with a slope of 1010. What is the value of gg?\newlineg=___g = \_\_\_

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Q. The points (5,7)(-5,7) and (6,g)(-6,g) fall on a line with a slope of 1010. What is the value of gg?\newlineg=___g = \_\_\_
  1. Identify Points and Slope: Identify the given points and slope.\newlinePoints: (5,7)(-5, 7) and (6,g)(-6, g)\newlineSlope: 1010\newlineUse the slope formula: Slope=y2y1x2x1\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}\newline10=g76+510 = \frac{g - 7}{-6 + 5}
  2. Use Slope Formula: Simplify the equation.\newline10=g7110 = \frac{g - 7}{-1}\newlineMultiply both sides by 1-1 to isolate g7g - 7.\newline10×1=g71×110 \times -1 = \frac{g - 7}{-1} \times -1\newline10=g7-10 = g - 7
  3. Simplify Equation: Solve for gg.10=g7-10 = g - 7Add 77 to both sides.10+7=g-10 + 7 = g3=g-3 = g

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