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The points (3,−3)(3,-3) and (0,g)(0,g) fall on a line with a slope of −3-3. What is the value of gg?\newlineg = ____

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Q. The points (3,−3)(3,-3) and (0,g)(0,g) fall on a line with a slope of −3-3. What is the value of gg?\newlineg = ____
  1. Slope Formula: We know the formula for the slope mm between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:\newlinem=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}\newlineWe are given the slope m=−3m = -3, point (3,−3)(3, -3) as (x1,y1)(x_1, y_1), and point (0,g)(0, g) as (x2,y2)(x_2, y_2).\newlineLet's plug these values into the slope formula to find gg.\newline−3=g−(−3)0−3-3 = \frac{g - (-3)}{0 - 3}
  2. Plug in Values: Now, we simplify the equation:\newline−3=(g+3)−3-3 = \frac{(g + 3)}{-3}\newlineTo solve for gg, we multiply both sides by −3-3:\newline−3×−3=(g+3)-3 \times -3 = (g + 3)
  3. Simplify Equation: Next, we calculate the left side of the equation:\newline9=g+39 = g + 3\newlineNow, we subtract 33 from both sides to isolate gg:\newline9−3=g9 - 3 = g
  4. Isolate Variable: Finally, we find the value of gg:6=g6 = g

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