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The points (−3,2)(-3,2) and (−2,r)(-2,r) fall on a line with a slope of −6-6. What is the value of rr?\newliner=___r = \_\_\_

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Q. The points (−3,2)(-3,2) and (−2,r)(-2,r) fall on a line with a slope of −6-6. What is the value of rr?\newliner=___r = \_\_\_
  1. Identify slope formula: Identify the formula for slope between two points.\newlineThe slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1), where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of the two points.
  2. Substitute points and slope: Substitute the given points and slope into the slope formula.\newlineUsing points (−3,2)(-3,2) as (x1,y1)(x_1, y_1) and (−2,r)(-2,r) as (x2,y2)(x_2, y_2), and slope = −6-6:\newline(−6)=(r−2)(−2+3)(-6) = \frac{(r - 2)}{(-2 + 3)}
  3. Solve for r: Solve for r.\newline−6=r−2-6 = r - 2\newliner=−6+2r = -6 + 2\newliner=−4r = -4

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