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The points (1,j)(1,j) and (2,5)(2,5) fall on a line with a slope of 88. What is the value of jj?\newlinej=___j = \_\_\_

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Full solution

Q. The points (1,j)(1,j) and (2,5)(2,5) fall on a line with a slope of 88. What is the value of jj?\newlinej=___j = \_\_\_
  1. Calculate Slope: Points: (1,j)(1, j) and (2,5)(2, 5); Slope: 88. Using the slope formula: Slope = y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}. 8=5−j2−18 = \frac{5 - j}{2 - 1}
  2. Simplify Equation: Simplify the equation: 8=5−j8 = 5 - j
  3. Solve for j: Solve for jj:8=5−j8 = 5 - j8−5=j8 - 5 = jj=3j = 3

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