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The points (0,8)(0,8) and (8,p)(8,p) fall on a line with a slope of −2-2. What is the value of pp?\newlinep=p = ____

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Full solution

Q. The points (0,8)(0,8) and (8,p)(8,p) fall on a line with a slope of −2-2. What is the value of pp?\newlinep=p = ____
  1. Identify Points and Slope: Identify the given points and slope.\newlinePoints: (0,8)(0, 8) and (8,p)(8, p)\newlineSlope: −2-2\newlineUse the slope formula: Slope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−2=p−88−0-2 = \frac{p - 8}{8 - 0}
  2. Use Slope Formula: Simplify and solve for pp.\newline−2=p−88-2 = \frac{p - 8}{8}\newlineMultiply both sides by 88 to clear the fraction.\newline−2×8=(p−8)-2 \times 8 = (p - 8)\newline−16=p−8-16 = p - 8
  3. Simplify and Solve: Isolate pp.−16=p−8-16 = p - 8Add 88 to both sides.−16+8=p-16 + 8 = p−8=p-8 = p

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