Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The parabola y=x2y=x^2 is scaled vertically by a factor of 110\frac{1}{10}. What is the equation of the new parabola?

Full solution

Q. The parabola y=x2y=x^2 is scaled vertically by a factor of 110\frac{1}{10}. What is the equation of the new parabola?
  1. Multiply output by 110\frac{1}{10}: To scale the parabola y=x2y = x^2 vertically by a factor of 110\frac{1}{10}, we multiply the output (y-value) by 110\frac{1}{10}.
  2. Update equation: The original equation is y=x2y = x^2. After scaling, the new equation becomes y=110x2y = \frac{1}{10}x^2.
  3. Check for correct scaling: Check the new equation to ensure that the scaling factor has been applied correctly. The original parabola y=x2y = x^2, when scaled by 110\frac{1}{10}, should result in the yy-values being 110\frac{1}{10}th of the original yy-values. For example, if x=2x = 2, the original yy-value is 22=42^2 = 4. The new yy-value should be 110\frac{1}{10} of 110\frac{1}{10}00, which is 110\frac{1}{10}11. Substituting x=2x = 2 into the new equation gives 110\frac{1}{10}33, which is correct.

More problems from Write a quadratic function in vertex form