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Let’s check out your problem:
6
6
6
. The number line below represents the solution set to which inequality?
\newline
A.
16
+
x
<
23
16+x<23
16
+
x
<
23
\newline
B.
5
x
≥
35
5 x \geq 35
5
x
≥
35
\newline
C.
x
−
3
≤
4
x-3 \leq 4
x
−
3
≤
4
\newline
D.
x
2
>
3.5
\frac{x}{2}>3.5
2
x
>
3.5
\newline
CManeuvering the Middle LLC,
20
20
20
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Math Problems
Grade 6
Estimate products of mixed numbers
Full solution
Q.
6
6
6
. The number line below represents the solution set to which inequality?
\newline
A.
16
+
x
<
23
16+x<23
16
+
x
<
23
\newline
B.
5
x
≥
35
5 x \geq 35
5
x
≥
35
\newline
C.
x
−
3
≤
4
x-3 \leq 4
x
−
3
≤
4
\newline
D.
x
2
>
3.5
\frac{x}{2}>3.5
2
x
>
3.5
\newline
CManeuvering the Middle LLC,
20
20
20
Solve Inequality A:
First, let's solve inequality A:
16
+
x
<
23
16 + x < 23
16
+
x
<
23
. Subtract
16
16
16
from both sides to isolate
x
x
x
:
x
<
23
−
16
x < 23 - 16
x
<
23
−
16
. Calculate:
x
<
7
x < 7
x
<
7
.
Solve Inequality B:
Now, solve inequality B:
5
x
≥
35
5x \geq 35
5
x
≥
35
.
\newline
Divide both sides by
5
5
5
to isolate
x
x
x
:
x
≥
35
5
x \geq \frac{35}{5}
x
≥
5
35
.
\newline
Calculate:
x
≥
7
x \geq 7
x
≥
7
.
Solve Inequality C:
Next, solve inequality C:
x
−
3
≤
4
x - 3 \leq 4
x
−
3
≤
4
. Add
3
3
3
to both sides to isolate
x
x
x
:
x
≤
4
+
3
x \leq 4 + 3
x
≤
4
+
3
. Calculate:
x
≤
7
x \leq 7
x
≤
7
.
Solve Inequality D:
Finally, solve inequality D:
x
2
>
3.5
\frac{x}{2} > 3.5
2
x
>
3.5
. Multiply both sides by
2
2
2
to isolate x:
x
>
3.5
×
2
x > 3.5 \times 2
x
>
3.5
×
2
. Calculate:
x
>
7
x > 7
x
>
7
.
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3
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\newline
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\newline
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3.515
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3.515
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4.75
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5
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×
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0
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\square \times 10^{\square}
□
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1.501
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3.95
×
1
0
4
3.95 \times 10^{4}
3.95
×
1
0
4
expressed in scientific notation?
\newline
Answer:
□
×
1
0
□
\square \times 10^{\square}
□
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What is the quotient of
6.096
×
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0
9
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and
6.35
×
1
0
5
6.35 \times 10^{5}
6.35
×
1
0
5
expressed in scientific notation?
\newline
Answer:
□
×
1
0
□
\square \times 10^{\square}
□
×
1
0
□
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Question
Solve for
x
x
x
:
\newline
3
x
+
5
=
2
(
x
−
4
)
3x+5=2(x-4)
3
x
+
5
=
2
(
x
−
4
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\newline
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As a fraction in simplest terms, what would you multiply the first number by to get the second?
\newline
First number:
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6
Second number:
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33
33
\newline
6
⋅
□
=
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6 \cdot \square=33
6
⋅
□
=
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