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Solve for xx:\newline3x+5=2(x4)3x+5=2(x-4)

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Q. Solve for xx:\newline3x+5=2(x4)3x+5=2(x-4)
  1. Distribute 22 to both sides: First, we need to distribute the 22 on the right side of the equation to both xx and 4-4. So, we have: 3x+5=2x83x + 5 = 2x - 8
  2. Subtract 2x2x from both sides: Next, we subtract 2x2x from both sides to get the xx terms on one side and the constants on the other side.\newline3x2x+5=2x2x83x - 2x + 5 = 2x - 2x - 8\newlineThis simplifies to:\newlinex+5=8x + 5 = -8
  3. Subtract 55 from both sides: Now, we subtract 55 from both sides to solve for xx.x+55=85x + 5 - 5 = -8 - 5This simplifies to:x=13x = -13

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