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The function
h is defined by
h(x)=kx^(2)-7. If
h(5)=-57, what is the value of
k ?

The function $h$ is defined by $h(x)=kx^{2}-7$ . If $h(5)=-57$ , what is the value of $k$ ?

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Find the vertex of the transformed function

Full solution

Q. The function

h

is defined by

h(x)=kx^{2}-7

. If

h(5)=-57

, what is the value of

k

?

Substitute $x = 5$ : Step $1$ : Substitute $x = 5$ into the function $h(x) = kx^2 - 7$ to find $k$ . $\newline$ $h(5) = k(5)^2 - 7 = -57$ $\newline$ $25k - 7 = -57$
Find $k$ : Step $2$ : Solve for $k$ . $25k - 7 + 7 = -57 + 7$ $25k = -50$ $k = \frac{-50}{25}$ $k = -2$

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