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The equation of a parabola is y=x2+6x+10y = x^2 + 6x + 10. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+6x+10y = x^2 + 6x + 10. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete square: Complete the square to transform the given equation into vertex form.\newlineThe given equation is y=x2+6x+10y = x^2 + 6x + 10. To complete the square, we need to find the value that makes x2+6xx^2 + 6x a perfect square trinomial. This value is (6/2)2=32=9(6/2)^2 = 3^2 = 9. We will add and subtract 99 to the equation.
  3. Add/subtract value: Add and subtract the value found in Step 22 to the equation.\newliney=x2+6x+99+10y = x^2 + 6x + 9 - 9 + 10\newlineNow, we can rewrite the equation as y=(x2+6x+9)+109y = (x^2 + 6x + 9) + 10 - 9.
  4. Factor and simplify: Factor the perfect square trinomial and simplify the constant terms.\newliney=(x+3)2+109y = (x + 3)^2 + 10 - 9\newliney=(x+3)2+1y = (x + 3)^2 + 1\newlineNow, the equation is in vertex form, where the vertex is (3,1)(-3, 1).

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