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The equation of a parabola is y=x24x+7y = x^2 - 4x + 7. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x24x+7y = x^2 - 4x + 7. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by the equation y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the square: Complete the square to rewrite the given equation in vertex form.\newlineWe have the equation y=x24x+7y = x^2 - 4x + 7. To complete the square, we need to find the value that makes x24xx^2 - 4x a perfect square trinomial. We do this by taking half of the coefficient of xx, squaring it, and adding it to and subtracting it from the equation.\newlineHalf of 4-4 is 2-2, and (2)2=4(-2)^2 = 4. So we add and subtract 44 to the equation.
  3. Add squared number: Add and subtract the squared number to the equation.\newliney=x24x+4+74y = x^2 - 4x + 4 + 7 - 4\newlineNow we have added 44 and subtracted 44, which keeps the equation balanced.
  4. Group and combine: Group the perfect square trinomial and combine the constants.\newliney=(x24x+4)+74y = (x^2 - 4x + 4) + 7 - 4\newliney=(x2)2+3y = (x - 2)^2 + 3\newlineNow we have the equation in vertex form, where (x2)2(x - 2)^2 is the perfect square trinomial and 33 is the combined constant.

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