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The equation of a parabola is y=x2+4x+5y = x^2 + 4x + 5. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+4x+5y = x^2 + 4x + 5. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the square: Complete the square to transform the given equation into vertex form.\newlineWe have the equation y=x2+4x+5y = x^2 + 4x + 5. To complete the square, we need to find the value that makes x2+4xx^2 + 4x a perfect square trinomial. This value is (4/2)2=22=4(4/2)^2 = 2^2 = 4. We will add and subtract this value inside the equation.
  3. Add and subtract value: Add and subtract the value found in Step 22 to the equation.\newliney=x2+4x+44+5y = x^2 + 4x + 4 - 4 + 5\newlineNow, we have added 44 and subtracted 44, which keeps the equation balanced.
  4. Rewrite equation: Rewrite the equation by grouping the perfect square trinomial and combining the constants.\newliney=(x2+4x+4)4+5y = (x^2 + 4x + 4) - 4 + 5\newliney=(x+2)2+1y = (x + 2)^2 + 1\newlineNow, the equation is in vertex form, where (h,k)=(2,1)(h, k) = (-2, 1).

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