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The equation of a parabola is y=x22x8y = x^2 - 2x - 8. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x22x8y = x^2 - 2x - 8. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the square: Complete the square to transform the given equation into vertex form.\newlineThe given equation is y=x22x8y = x^2 - 2x - 8. To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the xx-terms.\newlineThe coefficient of xx is 2-2, so we take half of it, which is 1-1, and then square it to get 11. We will add and subtract this value inside the equation.\newliney=x22x+118y = x^2 - 2x + 1 - 1 - 8
  3. Rewrite equation: Rewrite the equation by grouping the perfect square trinomial and combining the constants.\newliney=(x22x+1)18y = (x^2 - 2x + 1) - 1 - 8\newliney=(x1)29y = (x - 1)^2 - 9\newlineNow the equation is in vertex form, where the vertex (h,k)(h, k) is (1,9)(1, -9).

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