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The equation of a parabola is y=x22x5y = x^2 - 2x - 5. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x22x5y = x^2 - 2x - 5. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the Square: Complete the square to rewrite the equation y=x22x5y = x^2 - 2x - 5 in vertex form.\newlineFirst, we need to complete the square for the xx-terms. To do this, we take the coefficient of the xx-term, divide it by 22, and square it. For the equation y=x22x5y = x^2 - 2x - 5, the coefficient of xx is 2-2. Dividing it by 22 gives us 1-1, and squaring it gives us 11. We will add and subtract this value inside the equation.
  3. Add Square Value: Add and subtract the square of half the xx-coefficient inside the equation.\newlineWe have y=x22x+115y = x^2 - 2x + 1 - 1 - 5. We added and subtracted 11 to complete the square.
  4. Group and Combine: Group the perfect square trinomial and combine the constants.\newlineNow we group the terms to form a perfect square trinomial and combine the constants: y=(x22x+1)15y = (x^2 - 2x + 1) - 1 - 5, which simplifies to y=(x1)26y = (x - 1)^2 - 6.
  5. Write in Vertex Form: Write the equation in vertex form.\newlineThe equation in vertex form is y=(x1)26y = (x - 1)^2 - 6. This is the vertex form of the given parabola, where the vertex is (1,6)(1, -6).

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