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The equation of a parabola is y=x2+10x+20y = x^2 + 10x + 20. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+10x+20y = x^2 + 10x + 20. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the Square: Complete the square to transform the given equation into vertex form.\newlineWe start with the given equation y=x2+10x+20y = x^2 + 10x + 20. To complete the square, we need to find the value that makes x2+10xx^2 + 10x a perfect square trinomial. This value is (10/2)2=25(10/2)^2 = 25. We will add and subtract 2525 inside the equation.
  3. Add and Subtract: Add and subtract 2525 to the equation.\newliney=x2+10x+2525+20y = x^2 + 10x + 25 - 25 + 20\newlineNow, we have added 2525 and subtracted 2525, which keeps the equation balanced.
  4. Rewrite Equation: Rewrite the equation by grouping the perfect square trinomial and combining the constants.\newliney=(x2+10x+25)25+20y = (x^2 + 10x + 25) - 25 + 20\newliney=(x+5)25y = (x + 5)^2 - 5\newlineWe have now written the equation in vertex form, where (x+5)2(x + 5)^2 is the perfect square trinomial and 5-5 is the result of combining the constants.

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