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The equation of a parabola is y=x2+10x+16y = x^2 + 10x + 16. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2+10x+16y = x^2 + 10x + 16. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify Vertex Form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by the equation y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the Square: Complete the square to rewrite the given equation in vertex form.\newlineWe have the equation y=x2+10x+16y = x^2 + 10x + 16. To complete the square, we need to find the value that makes x2+10xx^2 + 10x a perfect square trinomial. This value is (10/2)2=25(10/2)^2 = 25. We will add and subtract 2525 inside the equation.
  3. Add and Subtract: Add and subtract 2525 to the equation.\newliney=x2+10x+16y = x^2 + 10x + 16\newliney=x2+10x+2525+16y = x^2 + 10x + 25 - 25 + 16\newlineNow, we have added 2525 and subtracted 2525, which keeps the equation balanced.
  4. Group and Combine: Group the perfect square trinomial and combine the constants.\newliney=(x2+10x+25)25+16y = (x^2 + 10x + 25) - 25 + 16\newliney=(x+5)29y = (x + 5)^2 - 9\newlineNow, we have the equation in vertex form, where (x+5)2(x + 5)^2 is the perfect square trinomial and 9-9 is the combination of the constants.

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