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The equation of a line is
y+4=6x+13
What is the value of
y at the point where the line crosses the
y-axis?

The equation of a line is $y+4=6 x+13$ $\newline$ What is the value of $y$ at the point where the line crosses the $y$ -axis?

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Characteristics of quadratic functions: equations

Full solution

Q. The equation of a line is

y+4=6 x+13

\newline

What is the value of

y

at the point where the line crosses the

y

-axis?

Set $x$ to $0$ : To find where the line crosses the y-axis, we need to set $x$ to $0$ in the equation $y + 4 = 6x + 13$ .
Substitute $x$ into equation: Substitute $x = 0$ into the equation: $y + 4 = 6(0) + 13$ .
Simplify the equation: Simplify the equation: $y + 4 = 0 + 13$ .
Subtract $4$ to solve: Subtract $4$ from both sides to solve for $y$ : $y = 13 - 4$ .
Calculate y value: Calculate the value of y: $y = 9$ .

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