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The equation of a circle is \newline(x+3)2+(y4)2=49(x+3)^{2}+(y-4)^{2}=49. What are the center and radius of the circle?\newlineChoose 11 answer:\newlineA The center is \newline(3,4)(3,4) and the radius is 77.\newlineB The center is \newline(3,4)(-3,4) and the radius is 77.\newline(C) The center is \newline(3,4)(-3,-4) and the radius is 77.\newline(D) The center is \newline(3,4)(-3,4) and the radius is 4949.

Full solution

Q. The equation of a circle is \newline(x+3)2+(y4)2=49(x+3)^{2}+(y-4)^{2}=49. What are the center and radius of the circle?\newlineChoose 11 answer:\newlineA The center is \newline(3,4)(3,4) and the radius is 77.\newlineB The center is \newline(3,4)(-3,4) and the radius is 77.\newline(C) The center is \newline(3,4)(-3,-4) and the radius is 77.\newline(D) The center is \newline(3,4)(-3,4) and the radius is 4949.
  1. Rewrite Equation: Rewrite the given equation in standard form to identify the center and radius.
  2. Identify Center: Identify the center (h,k)(h, k) by comparing with the standard form of a circle equation, (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.
  3. Determine Radius: Determine the radius by taking the square root of 4949.

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